Leetcode•Aug 05, 2025
Random Pick with Weight
Hazrat Ali
Leetcode
You need to implement the function pickIndex()
, which randomly picks an index in the range [0, w.length - 1]
(inclusive) and returns it. The probability of picking an index i
is w[i] / sum(w)
.
- For example, if
w = [1, 3]
, the probability of picking index0
is1 / (1 + 3) = 0.25
(i.e.,25%
), and the probability of picking index1
is3 / (1 + 3) = 0.75
(i.e.,75%
).
Example 1:
Input ["Solution","pickIndex"] [[[1]],[]] Output [null,0] Explanation Solution solution = new Solution([1]); solution.pickIndex(); // return 0. The only option is to return 0 since there is only one element in w.
Example 2:
Input ["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"] [[[1,3]],[],[],[],[],[]] Output [null,1,1,1,1,0] Explanation Solution solution = new Solution([1, 3]); solution.pickIndex(); // return 1. It is returning the second element (index = 1) that has a probability of 3/4. solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 0. It is returning the first element (index = 0) that has a probability of 1/4. Since this is a randomization problem, multiple answers are allowed. All of the following outputs can be considered correct: [null,1,1,1,1,0] [null,1,1,1,1,1] [null,1,1,1,0,0] [null,1,1,1,0,1] [null,1,0,1,0,0] ...... and so on.
Solution
const getRandomArbitrary = (min, max) => Math.random() * (max - min) + min;
const getRandomInt = (min, max) => Math.floor(Math.random() * (max - min + 1)) + min;
class Solution {
/**
* @param {number[]} w
*/
constructor(w) {
for (let i = 1; i < w.length; i++) {
w[i] += w[i - 1];
}
this.wSums = w;
}
/**
* @return {number}
*/
pickIndex() {
const n = this.wSums.length;
const idx = getRandomInt(1, this.wSums[n - 1]);
let lo = 0;
let hi = n - 1;
while (lo < hi) {
const mid = lo + Math.floor((hi - lo) / 2);
if (this.wSums[mid] === idx) {
return mid;
} else if (this.wSums[mid] < idx) {
lo = mid + 1;
} else {
hi = mid;
}
}
return lo;
}
}